Int cos4x+1/cotx-tanx
Nettet1. okt. 2024 · If ∫ cos 4x + 1 cot x − tan x dx = k cos 4x + c ∫ cos 4 x + 1 cot x - tan x d x = k cos 4 x + c, then k= (A) − 1 4 - 1 4 (B) − 1 2 - 1 2 (C) − 1 8 - 1 8 (D) none of these … NettetIntegral of 1 Integral of sinx Integral of e^x^2 Integral of 1/2 Identical expressions; tanx/(three +cos^2x) tangent of x divide by (3 plus co sinus of e of squared x) tangent of x divide by (three plus co sinus of e of squared x) tanx/(3+cos2x) tanx/3+cos2x; tanx/(3+cos²x) tanx/(3+cos to the power of 2x) tanx/3+cos^2x
Int cos4x+1/cotx-tanx
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Nettet9. Another approach: We have 1 sin4x + cos4x, Multiply (1) by tan4x tan4x we obtain tan4x sin4x(1 + tan4x) = sec4x 1 + tan4x = (1 + tan2x)sec2x 1 + tan4x. Letting t = tanx, the integral turns out to be ∫1 + t2 1 + t4 dt = 1 2∫[ 1 t2 − √2t + 1 + 1 t2 + √2t + 1] dt = 1 2∫[ 1 (t − 1 √2)2 + 3 4 + 1 (t + 1 √2)2 + 3 4] dt. NettetIf `int(cos 4x+1)/(cotx-tanx)dx=a cos 4x+c,` then `a=` askedApr 18in Indefinite Integralby Somyek(121kpoints) class-12 integration-indefinite-integrals 0votes 1answer If : `int(sqrt(tanx)+sqrt(cotx))dx=m sin^(-1)(u)+c,` then : askedApr 18in Indefinite Integralby Somyek(121kpoints) class-12 integration-indefinite-integrals 0votes 1answer
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NettetWe will accordingly solve the integral for both the possibilities. Let I = ∫ [ (1/tanx) + cosec x + cot x + sec x] dx. We know that integral of sum of functions equals sum of integrals of the functions taken separately. ∴ I … Nettet`int(1+cos4x)/(cotx-tanx)\\ dx` - YouTube This is the Solution of Question From RD SHARMA book of CLASS 12 CHAPTER INDEFINITE INTEGRALS This Question is …
Nettet22. sep. 2016 · Sep 22, 2016. = sinx cosx + cosx sinx cosx sinx. = sin2x cosxsinx + cos2x cosxsinx cosx sinx. = sin2x+cos2x cosxsinx cosx sinx. = 1 cosxsinx cosx sinx. = 1 cosxsinx × sinx cosx.
Nettet22. jun. 2024 · `int(1+cos4x)/(cotx-tanx)\\ dx` - YouTube This is the Solution of Question From RD SHARMA book of CLASS 12 CHAPTER INDEFINITE INTEGRALS This Question is also … gut wolfersdorf thyrnauNettetIf `int(cos4x+1)/(cotx-tanx)dx=kcos4x+c`, then k= (A) `-1/4` (B) `-1/2` (C) `-1/8` (D) none of these boy black panther suitNettet你可能感兴趣的; 求sin^4x和sin^6x的不定积分. 一般的方法有三种： 1、运用余弦倍角公式； 2、运用递推公式； 3、运用复数方法,其中又可以有不同的具体的方法. gut wolfgangshof nürnbergNettet15. apr. 2024 · & Leftrightarrow 1 + cos 4x + sin 4x – 2 = 0 cr & Leftrightarrow cos 4x + sin 4x = 1 cr & Leftrightarrow sin left( {4x + {pi over 4}} right) = sin ... {1 over 2}) Với t = -2 ta có tanx + cotx = -2 (eqalign{& Leftrightarrow {tan ^2}x + 2tan x + 1 = 0 Rightarrow tan x = – 1 cr & Rightarrow x = – {pi over 4} + kpi ,k in Z{rm ... gut wolfgangshof“ in zirndorfNettet9. Another approach: We have 1 sin4x + cos4x, Multiply (1) by tan4x tan4x we obtain tan4x sin4x(1 + tan4x) = sec4x 1 + tan4x = (1 + tan2x)sec2x 1 + tan4x. Letting t = tanx, … boy black sweater vestNettetOldja meg matematikai problémáit ingyenes Math Solver alkalmazásunkkal, amely részletes megoldást is ad, lépésről lépésre. A Math Solver támogatja az alapszintű matematika, algebra, trigonometria, számtan és más feladatokat. boy blackout curtainsNettet求sinx的三次方对x的不定积分 gutworks beaconsfield